CAT Math Questions
November 16th, 2009 Posted in Quantitative Ability
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1. A group workers can complete a certain job in 9 days. But it so happens that every alternate day starting from the second day, 2 workers are withdraw from the job and every alternate day starting from the third day, one worker is added to the group. If it takes 17 days to finish the job now, find the number of workers who started the job?
a. 5
b. 10
c. 15
d. 20
2. How many numbers greater than 0 and less than a million can be formed with the digits of 0, 7 and 8?
a. 486
b. 1,084
c. 728
d. None of these
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November 17th, 2009 at 12:14 am
2)
2*3*3*3*3*3
November 17th, 2009 at 12:14 am
2) a 486
November 17th, 2009 at 12:23 am
1. (b) 10
2. (c) 728
November 17th, 2009 at 12:45 am
1)
Solution
amount of work done on first day = 1/9
amount of work done on day 2 = 1/9 – 2/(9n)
amount of work done on day 3 = 1/9 – 1/(9n)
amount of work done on day 4 = 1/9 – 3/(9n)
amount of work done on day 5 = 1/9 – 2/(9n)
SO adding all sud give 1
1 = 1/9 + (2/9- 3/9n) + (2/9 -5/9n) + …. 17 terms
1= 17/9 – 4( 6/9n + 7*2/9n)
8/9 = (4/9n)*(20)
8n = 80
n = 10
SO answer is 10 i.e. option (b)
November 17th, 2009 at 7:44 am
1)10
2)NON OF THESE…………….i got it as 731..
Is it correct…………..help
November 17th, 2009 at 8:20 am
@Praveen: We will post the answer tomorrow. Thanks
November 17th, 2009 at 1:04 pm
1.b
2.c
November 17th, 2009 at 10:51 pm
November 18th, 2009 at 5:39 am
1.b
November 20th, 2009 at 1:37 am
1.b
this type of problem can be solve by hit and try mathod
November 24th, 2009 at 5:24 am
Answer is b
December 13th, 2009 at 4:28 pm
this is a cool news. Thank you.