| Subcribe via RSS

FireUp Logo

Logical Questions

October 18th, 2009 Posted in Uncategorized
Directions for next 5 questions:
At the start of game, A and B between them had four times as much money as C while B & C together had three times as much as A. At the end, A & B between them had three times as much as C, while B & C together had twice as much as A. B finished Rs. 200 poorer at the end. A, B, C are the only players.
1. What fraction of the total money did C have at the beginning of the game ?
(a) 1/3
(b) 1/8
(c) 2/9
(d) 1/5
2. What fraction of the total money did A win (or lose)?
(a) won 1/12
(b) lost 1/6
(c) lost 1/3
(d) won 1/5
3. What amount did B start with ?
(a) Rs. 575
(b) Rs. 375
(c) Rs. 825
(d) Rs. 275
4. What amount did C win (lose)?
(a) lost Rs. 50
(b) won Rs. 75
(c) lost Rs. 125
(d) won Rs. 175
5. How much money did A have at the end of the game?
(a) Rs. 375
(b) Rs. 500
(c) Rs. 325
(d) Rs. 1100

Logical Questions: Directions for next 5 Logical Questions questions: Answer these Logical Questions on  the basis of the information given below.

At the start of game, A and B between them had four times as much money as C while B & C together had three times as much as A. At the end, A & B between them had three times as much as C, while B & C together had twice as much as A. B finished Rs. 200 poorer at the end. A, B, C are the only players.

1. What fraction of the total money did C have at the beginning of the game ?
(a) 1/3
(b) 1/8
(c) 2/9
(d) 1/5

2. What fraction of the total money did A win (or lose)?
(a) won 1/12
(b) lost 1/6
(c) lost 1/3
(d) won 1/5

3. What amount did B start with ?

(a) Rs. 575
(b) Rs. 375
(c) Rs. 825
(d) Rs. 275

4. What amount did C win (lose)?
(a) lost Rs. 50
(b) won Rs. 75
(c) lost Rs. 125
(d) won Rs. 175

5. How much money did A have at the end of the game?
(a) Rs. 375
(b) Rs. 500
(c) Rs. 325
(d) Rs. 1100

Related posts:

  1. Reasoning Questions with Solutions
  2. Logical Questions
  3. Logical & Aptitude Interview Questions

5 Responses to “Logical Questions”

  1. Arun Says:

    the answers to the questions are

    1. d
    2. a
    3. c
    4. b
    5. b
    let at start the amt are x,y,z
    then
    x+y= 4z
    y+z = 3x
    4x = 5z
    by this
    x = 5z/4
    y = 11x/5
    hence x,11x/5,4x/5

    let at the end of game are x’,y’,z’
    then x’+y’ = 3z’
    y’+z’=2x’
    z’ = 3x’/4
    y’ = 5x’/4
    hence x’,5x’/4,3x’/4
    since the total value remains the same which give reln btn x’ and x
    i.e; x’=4x/3
    hence
    the calc values are
    x=375 b=825 c=300
    after the end
    x= 500 b= 625 c = 375


  2. bratsi Says:

    1)d
    2)a
    3)c
    4)b
    5)b


  3. SAUVIK CHAKRABORTY Says:

    1-d
    2-c
    3-c
    4-b
    5-b


  4. Harindra Says:

    we have the following equation from the question
    Intial amount is A,B,C at the end of the game it is A1,B1,C1
    C = 4/5 A
    B = 11/5 A
    C1 = 3/5 B1
    A1 = 4/5 B1
    B1 = B – 200

    We have to first solve the 3rd part of the problem. since A,B,C and A1, B1 , C1 has to be integers the only opition for the 3rd part is option C (825)

    Now Since B is known we can find all the variables left

    A = 375
    B = 825
    C = 300

    A1 = 500
    B1 = 625
    C1 = 375

    now
    question 1 is
    option d (1/5)
    question 2 is
    option a (1/12)
    question 3 already solved
    option C (825)
    Question 4 is
    option b (75)
    question 5 is
    option b (500)


  5. admin Says:

    For explanation and correct answers of the above caselet check ARUN’s Comment.

    Well Done All Of You!!


Leave a Reply