## Logical Questions

October 18th, 2009 Posted in Uncategorized
Directions for next 5 questions:
At the start of game, A and B between them had four times as much money as C while B & C together had three times as much as A. At the end, A & B between them had three times as much as C, while B & C together had twice as much as A. B finished Rs. 200 poorer at the end. A, B, C are the only players.
1. What fraction of the total money did C have at the beginning of the game ?
(a) 1/3
(b) 1/8
(c) 2/9
(d) 1/5
2. What fraction of the total money did A win (or lose)?
(a) won 1/12
(b) lost 1/6
(c) lost 1/3
(d) won 1/5
(a) Rs. 575
(b) Rs. 375
(c) Rs. 825
(d) Rs. 275
4. What amount did C win (lose)?
(a) lost Rs. 50
(b) won Rs. 75
(c) lost Rs. 125
(d) won Rs. 175
5. How much money did A have at the end of the game?
(a) Rs. 375
(b) Rs. 500
(c) Rs. 325
(d) Rs. 1100

Logical Questions: Directions for next 5 Logical Questions questions: Answer these Logical Questions on  the basis of the information given below.

At the start of game, A and B between them had four times as much money as C while B & C together had three times as much as A. At the end, A & B between them had three times as much as C, while B & C together had twice as much as A. B finished Rs. 200 poorer at the end. A, B, C are the only players.

1. What fraction of the total money did C have at the beginning of the game ?
(a) 1/3
(b) 1/8
(c) 2/9
(d) 1/5

2. What fraction of the total money did A win (or lose)?
(a) won 1/12
(b) lost 1/6
(c) lost 1/3
(d) won 1/5

(a) Rs. 575
(b) Rs. 375
(c) Rs. 825
(d) Rs. 275

4. What amount did C win (lose)?
(a) lost Rs. 50
(b) won Rs. 75
(c) lost Rs. 125
(d) won Rs. 175

5. How much money did A have at the end of the game?
(a) Rs. 375
(b) Rs. 500
(c) Rs. 325
(d) Rs. 1100

Related posts:

### 5 Responses to “Logical Questions”

1. Arun Says:

the answers to the questions are

1. d
2. a
3. c
4. b
5. b
let at start the amt are x,y,z
then
x+y= 4z
y+z = 3x
4x = 5z
by this
x = 5z/4
y = 11x/5
hence x,11x/5,4x/5

let at the end of game are x’,y’,z’
then x’+y’ = 3z’
y’+z’=2x’
z’ = 3x’/4
y’ = 5x’/4
hence x’,5x’/4,3x’/4
since the total value remains the same which give reln btn x’ and x
i.e; x’=4x/3
hence
the calc values are
x=375 b=825 c=300
after the end
x= 500 b= 625 c = 375

2. bratsi Says:

1)d
2)a
3)c
4)b
5)b

3. SAUVIK CHAKRABORTY Says:

1-d
2-c
3-c
4-b
5-b

4. Harindra Says:

we have the following equation from the question
Intial amount is A,B,C at the end of the game it is A1,B1,C1
C = 4/5 A
B = 11/5 A
C1 = 3/5 B1
A1 = 4/5 B1
B1 = B – 200

We have to first solve the 3rd part of the problem. since A,B,C and A1, B1 , C1 has to be integers the only opition for the 3rd part is option C (825)

Now Since B is known we can find all the variables left

A = 375
B = 825
C = 300

A1 = 500
B1 = 625
C1 = 375

now
question 1 is
option d (1/5)
question 2 is
option a (1/12)