## Math Questions

**Direction for next 3 Questions:** Answer the Questions on the basis of the text given below.

** **

There are 3 bottles and a jug. The bottles each have a capacity of 5 liters but are partially filled with water. The jug also has some water in it. The sum of the water in the jug and water in the first bottle is half of the total jug capacity. When the first bottle and third bottle are emptied into the jug, it contains 6 liters of water. When the second and the third bottle are emptied into the jug, it contains 7 liters of water. When all the bottles are poured into the jug, it’s filled to its capacity. The first and second bottles contain a total of 7 liters.

**1.** What percentage of total capacity of the bottles is filled with water?

**a) **20% – 40%

**b) **40% – 60%

**c) **60% – 80%

**d)** 30% – 50%

**2.** What is the capacity of the jug? (In liters)

**a) **7

**b) **8

**c) **9

**d) **10

**3.** How much water does the jug already contain (in liters)?

**a)** 3

**b) **4

**c)** 1

**d) **2

Related posts:

mickySays:December 12th, 2009 at 7:38 am

B

D

D

mickySays:December 12th, 2009 at 7:39 am

hey guys i got a call from iift.

vishnuSays:December 12th, 2009 at 9:36 am

Yup!Micky is right!

its BDD!

Congrats Micky!

all the best for the further rounds!

UttamSays:December 13th, 2009 at 2:19 am

1. b

2. d

3. d

UttamSays:December 13th, 2009 at 2:36 am

Explanation,

Say initially 3 bottles have x,y and z (First=x,y=second,z=third)

and jar has j.All are in liter.

Say jar capacity=m liter

So fror the question,

we get,

j+x=m/2—–(1)

x+z+j=6—–(2)

y+z+j=7—–(3)

x+y+z+j=m—-(4)

x+y=7—–(5)

By Equ3-equ2,

y-x=1—-(6)

From equ(5)and equ (6),

we get x=3 and y=4.

Putting x=3 and y=4 in equ 2 and equ 4, we get,

z+j=3 and z+j=m-7 so,m-7=3 or m=10,

so putting x=3 and m=10, in equ 1, we get,

j+3=10/2

or j=2

so z=3-j=3-2=1

so x+y+z=3+4+1=8

1. so the percentage of total capacity of the bottles is filled with water=(8/15)*100%=160/3% which is

approx 53.33% so ( 40% – 60%) is the write answer.

2.The capacity of the jug =M=10 L

So the answer is D.

3.The jug already contains j liter = 2 liter water .So answer is D.

ShreyasiSays:December 13th, 2009 at 10:32 pm

Yes. The answer is

b

d

d

I agree with Uttam’s solution. My equations are slightly different.

adminSays:December 13th, 2009 at 11:01 pm

Answer to questions 1 to 3::Let b1 stands for water in bottle 1, b2 stands for water in bottle 2 and b3 stands for water in bottle 3. and j stands for jug.

b1+ b3 + j = 6 … ( i )

b2+ b3 + j = 7 …( ii )

b1+ j = half jug … ( iii )

b1+ b2 + b3 + j = full jug … ( iv )

b1 + b2 = 7 … (v)

From (i), (ii) and (v), (ii) – (i) + (v)

2 b2 = 8, b2 = 4 Therefore, b1 = 3.

Also b3 + j = 3

Therefore, b1 + b2 + b3 + j = 7 + 3 = 10 = Full jug capacity

Thus we get all the values. Also b1 + j = 10/2 = 5

Therefore, b1 = 3, j = 5 – 3 = 2.

b3 = 3 – 2 = 1

1.b(3 + 4 + 1) / 15 = 8/15 > 50%, hence b) 40% – 60%

2.d 10 liters3.d 2 litersuberVU - social commentsSays:December 14th, 2009 at 6:37 am

Social comments and analytics for this post…This post was mentioned on Twitter by FIREUPCAT: Published a new post: Math Questions http://tinyurl.com/y98alhw…