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A big hello to all CAT 2009 aspirants,
By now you must have immersed yourselves into preparing, preparing and preparing for the d-day. Well, this mail will definitely bring some cheer.
Great news for all you guys!!
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October 7th, 2009 at 4:40 am
46%
October 7th, 2009 at 11:16 am
let initial weights be 72 and 28
20%of 72 is now 80 % of x
therefore x= 18
therefore 72 has reduced to 18 loss = 54
loss % =54/100= 54%
hence (a)
October 8th, 2009 at 6:12 am
The answer to the 2nd question is
52
which is 100% true
since it is difficult to write the powers i cant give the solution but the concept used is power reduction ie; power 1000 is reduced to 1 .
October 8th, 2009 at 10:47 am
The answer to the grapes question is 46%
72 fresh
28 dried
water | solid
72*4/5 72/5 fresh
28/5 28*4/5 solid
since the conversion of the fresh to dried will result in loss of water will be reduction hence the reduction is 72*19 /25 (72*4/5-72*4/25) = 46.08%
October 9th, 2009 at 8:38 am
the answer of 128^1000 divided by 153 is option a (52)
October 10th, 2009 at 7:23 am
percents of fresh grapes in basket: x
percents of dried grapes in basket: 1-x
weights of a fresh grape: a
weights of a dried grape: 0.4*a
we have: (a*x)/0.72=0,4*a(1-x)/0.28=0.6*a*x+0.4*a
=> x= 0.72(0.6*x+0.4)
=> x=36/71
percentage reduction: y
we have weights of total grapes in basket:m
m= 0.6*a*x+0.4*a=a(0.6*36/71+0.4)=a*50/71
=> y=a*x(0.8-0.2)/(a*50/71)=0.6*x*(71/50)
y=0.6*(36/71)*(71/50)=0.43