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1. Machine A can produce 500 components a day while machine B only 400. The monthly maintenance cost for machine A is $1500 while that for machine B is $550. If each component generates an income of $10 what is the least number of days per month that the plant has to work to justify the usage of machine A instead of machine B?
a) 6
b) 7
c) 9
d) 10
e) 11
2. A man travels form A to B at a speed of x km/h. He then rests at B or x hours. He then travels from B to C at a speed of 2x km/h and rests at C for 2x hours. He moves further to D at a speed twice as that between B and C. He thus reaches D in 16 hours. If distances A-B, B-C, C-D are all equal to 12 km, the time for which he rested at B could be:
a) 3 hours
b) 6 hours
c) 2 hours
d) 4 hours
e) 5 hours
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November 15th, 2009 at 11:29 pm
1)A
2)C
November 15th, 2009 at 11:41 pm
answer to 2 is option a)3 hours
eqn is :::::
12/x + 12/2x +12/4x + x + 2x = 16
here:12/x=time taken from a to b
= rest taken at b
:12/2x=time taken from b to c
:12/4x=time taken from c to d
:2x=rest taken at c
total time taken=16 hours
November 16th, 2009 at 12:20 am
1-b
2-a
November 16th, 2009 at 12:49 am
2. a
November 16th, 2009 at 2:35 am
2)
total time travellenig from A to D =16 h
12/x+x+12/2x+2x+12/4x=16
3x^2-16x+21=0
x=3 or x=3/7
November 16th, 2009 at 3:14 am
1) d
2) a
November 16th, 2009 at 3:17 am
data in question 1 is doubtful.
November 16th, 2009 at 5:29 am
1)d
2)a
November 16th, 2009 at 8:20 am
sory answers were wrong….. :-{
November 16th, 2009 at 11:28 pm
1. d) 10
Let x be the number of days that need to be worked
500x – 1500 > 400x – 550
100x > 950
x > 9.5
2. a) 3 hours
We are given that AB = BC = CD = 12 km.
Therefore, Time taken to travel AB at a speed of x km/h is (12/x) hours.
This is followed by a break of x hours.
His speed from B to C is (2x) = 2x km/h
His speed from C to D is 2(2x) = 4x km/h.
Continuing on these lines, we get,
[(12/x) + x + (12/2x) + 2x + (12/4x)] = 16 hours.
Solving we get
x = 3 or x = 7/3. Only x = 3 is among the options
given, so that is the answer.
November 17th, 2009 at 12:13 am
@admin
In sol of 1st qus u havn’t multipied the profit of each component i.e. 10, while calculating
November 18th, 2009 at 5:54 am
1.d, 2.a
November 19th, 2009 at 10:38 am
@admin, like hitesh said your soln for 1 is incorrect.
actually even if plant operates for a single day it will make a profit of 3500 with mac A and 3450 with Mac B
so ans is .95 => 1 day not a option.
November 20th, 2009 at 2:05 am
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November 24th, 2009 at 5:25 am
2. A