Quantitative Ability Questions
November 29th, 2009 Posted in Quantitative Ability
Quantitative Ability Questions
Direction for next 2 Quantitative Ability Questions:
1. The first, second and middle terms of an A.P. are a, b and c respectively. Then the sum of the A.P. is
a. 2c(b – a)/c – a
b. 2c(c – a)/b – a + c
c. 2(c – a)/b – a
d. None of these
2. The average age of a husband, wife and their son, 3 years ago was 27 years and that of the wife and son 5 years ago was 21 years. The husband’s present age is
a. 32 years
b. 36 years
c. 38 years
d. 42 years
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November 29th, 2009 at 11:51 pm
b
c
November 30th, 2009 at 12:03 am
1. b
2. c
November 30th, 2009 at 12:36 am
2.c 38 years…
Fathers age = (27*3 +9) – (21*2+10)=38
can any one expalin me the first question…?? middle terms??
November 30th, 2009 at 3:00 am
2.c
November 30th, 2009 at 3:34 am
1)d
2) c
November 30th, 2009 at 3:41 am
well i would try by my understandin…!!
now 1st term=a,2nd = b, middle = c…
comm diff = d= b-a
no. of terms = n = (2*(c-a)/(b-a))+ 1
….(try by takin ne sample AP n check ..since middle term is single entity,try taking AP with odd terms)
and now solve usin formula.
November 30th, 2009 at 9:03 am
1)b
1st term=a
2nd term=b =>b=a+d =>d=b-a
middle term=c =>c=a+(n-1)/2*d =>n=2*(c-a)/(b-a)+1
now substitute a,n and d in the sum equation i.e.
sum=(n/2)*(2a+(n-1)d)
u get reqd option.
2)c
total age 3 years ago=27*3=81
total age now=81+3*3=90
wife+son’s age 5 years ago=21*2=42
wife+son’s age now=42+2*5=52
hence, husband’s age=90-52=38
November 30th, 2009 at 10:31 am
1.d
2.c
November 30th, 2009 at 11:21 pm
June 28th, 2010 at 10:17 pm
2.c