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Quantitative Ability Questions

December 6th, 2009 Posted in Quantitative Ability
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Quantitative Ability Questions:

1. A chord of length 32 cm is drawn inside a circle of radius 20 cm. And a point, whose distance from the centre of circle is 13 cm, is marked on the chord. Calculate the lengths of the segment of the chord made by this point.

a) 21 cm and 11 cm

b) 19 cm and 13 cm

c) 16 cm each

d) 18 cm and 14 cm

e) 17 cm and 15 cm

2. Tiwari sells samosas in boxes of different sizes. The samosas are priced at Rs. 2 / samosa up to 200 samosas. For every additional 20 samosas the price of the whole lot goes down by 10 paise / samosa. What should be the maximum size of the box that would maximize the revenue?

a) 240

b) 300

c) 400

d) 350

e) None of these

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8 Responses to “Quantitative Ability Questions”

  1. Govind Says:

    1.c..16cm
    2.e..


  2. uberVU - social comments Says:

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  3. Uttam Says:

    1. A

    2. B


  4. Uttam Says:

    Explanation:-

    1. Distance of the Permendicular from the center to cord which devides cord equal distance (32/2=16) = sqroot of (20^2-16^2)=12.
    Now the point on the cord having distance = 13 from the center is situated from the point of intersection between cord and perpendicular drawn from center = squroot of (13^2-12^2)=5.
    so required answer=16+5 and 16-5
    or 21 and 11.

    2. Say x is the extra somosa after 200.
    Revenew=(200+x)*(2-x/200)=400+x-x^2/200
    For Max(Revenew), d/dx(Revinew)=0
    so we get x=100
    so required answer=200+100=300.


  5. Govind Says:

    uttam i didn’t read the first question correctly so i agree with your answer,,although the texts are not very clear..

    And in second question your method seems to be oK but have you ysed 10 paise / samosa any where?


  6. Uttam Says:

    Hey Govind,
    Let say u are using extra x somosa.
    For every additional 20 samosas the price of the whole lot goes down by 10 paise / samosa.
    so for x somosa it will (x/20) * 10 paisa
    =(x/20)*(10/100) rupies
    =x/200
    so the cost per somosa will be 2-(x/200)
    Now u have (200+x) somosa
    So Revenie =F(x)=(200+x)*{2-(x/200)}
    now rest is same as above.
    Is it clear now????


  7. Govind Says:

    Agreed dude..Thanks for the lucid explanation..


  8. varsha Says:

    thats a nice explanation for 2nd qs…thanks 4 dat..


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