Quantitative Questions
December 8th, 2009 Posted in Quantitative Ability
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Quantitative Questions:
Direction for next 2 Quantitative questions:
1. Find the least number which on being divided by 5, 6, 8, 9, and 12 leaves in each case a remainder 1. But when divided by 13 leaves no remainder.
a) 2990
b) 3601
c) 2986
d) 1300
2. The inequality of b2 + 8b ≥ 9b + 14 is correct for
a) b ≥ 5 , b ≤ -5
b) b ≥ 5, b ≤ -4
c) b ≥ 6 , b ≤ -6
d) b ≥ 4, b ≤ -4
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December 8th, 2009 at 11:02 pm
b
b
December 8th, 2009 at 11:08 pm
1.b ..by substitution
2.b…
We get quadratic eequation of teh following form..
b(b-1)>= 14 the solution is..
[-infinity,-3.25]U[4.25,infinity +]
hence option 2
December 9th, 2009 at 12:46 am
1. b .
Back flow:-
Option A(2990) and D(1300) can be as they are divisible by 5.
Option C (2986) can not be valid as its not divisible by 13.
So left B (3601) which satisfies all required conditions.
So the answer is B.
2. b.
b^2 + 8b ≥ 9b + 14
or b^2 – b – 14>=0
taking equal,
we get b=-3.25 or b=4.25 (approx)
so solution b>=4.25 and b<=-3.25 (approx)
So ans is B (nearest integer)
December 9th, 2009 at 2:25 am
1. b
2. b
1. Backflow not reqd.
LCM(5,6,8,9,12) = 360
Now the number divided by 13 which leaves remainder 1
= 360k + 1 (360 k should be divisible by 13 and 1 is added as remainder)
= 3601 (putting k=10)
Hence (b)
2. rightly said b(b-1)>= 14
Quickly by substituting eqality values of 5,4,6 check!
Hence (b)
December 9th, 2009 at 3:50 am
b
b
December 9th, 2009 at 11:13 pm