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Quantative Ability Questions

November 2nd, 2009 Posted in Daily Question & Gyan
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1. A test has 50 questions. A student scores 1 mark for a correct answer, -1/3 for a wrong answer, and –1/6 for not attempting a question. If the net score of a student is 32, the number of questions answered wrongly by that student cannot be less than

a. 6

b.12

c. 3

d. 9

2. The sum of 3rd and 15th elements of an arithmetic progression is equal to the sum of 6th, 11th and 13th elements of the same progression. Then which element of the series should necessarily be equal to zero?

a. 1st

b. 9th

c. 12th

d. None of the above.

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11 Responses to “Quantative Ability Questions”

  1. SAUVIK CHAKRABORTY Says:

    1-c
    2-c


  2. ashukumar Says:

    1.c
    2.c


  3. Hitesh Says:

    Ans 1 c
    Ans 2 d

    very easy qus


  4. Hitesh Says:

    answer of 2nd question is 13th term


  5. MOHIT Says:

    answer for both the question is c


  6. Arun Says:

    Answer is
    1.c
    2.c


  7. Deepak Patel Says:

    ans1) c
    ans2) c


  8. INDU Says:

    1. c
    2. c


  9. admin Says:

    1. Ans. c
    Let the number of correct answer be ‘x’ number of wrong answers be ‘y’ and the number of questions not attempted be ‘z’
    Thus, x + y + z = 50 …………….(i)
    And x – y/3 z-6 = 32
    The second equations we get,
    7x – y = 242/7 + y
    Since, x and y are both integers, y cannot be 1 or 2. The minimum value that y can have is 3.

    2. Ans. c.
    If we consider the third term to be ‘x’
    The 15th term will be (x + 12d)
    6th term will be (x + 3d)
    11th term will be (x + 8d) and
    13th term will be (x + 10d)
    Thus, as per the given condition, 2x + 12d = 3x + 21d.
    Or x + 9d = 0
    x + 9d will be the 12th term.


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  11. sanjay Says:

    2. solution
    If first term is ‘a’ then
    3rd term = a+2d
    6th term = a+5d
    11th term = a+10d
    13th term = a+12d
    15th term = a+14d
    Given,
    (a+2d)+(a+14d) = (a+5d)+(a+10d)+(a+12d)
    a+11d = 0 ,ie the 12th term


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